Workbook Detail
Money Counting Dimes Hard — Set 88
You pay $5.00 for an item that costs $2.50. How much change do you get back?
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Answer: 250
- SubType
- make-change
- Difficulty
- hard
3 dimes + 2 dimes = ? cents
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Answer: 50
- SubType
- count-coins
- Difficulty
- hard
$2.33 + $1.28 = ?
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Answer: 361
- SubType
- add-money
- Difficulty
- hard
5 nickels + 4 nickels = ? cents
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Answer: 45
- SubType
- count-coins
- Difficulty
- hard
$1.57 + 89 cents = ?
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Answer: 246
- SubType
- add-money
- Difficulty
- hard
5 pennies + 2 nickels = ? cents
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Answer: 15
- SubType
- count-coins
- Difficulty
- hard
You pay $5.00 for an item that costs $4.30. How much change do you get back?
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Answer: 70
- SubType
- make-change
- Difficulty
- hard
$1.64 + $2.21 = ?
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Answer: 385
- SubType
- add-money
- Difficulty
- hard
$1.59 + $2.44 = ?
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Answer: 403
- SubType
- add-money
- Difficulty
- hard
1 quarter + 3 quarters = ? cents
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Answer: 100
- SubType
- count-coins
- Difficulty
- hard
You pay $1.00 for an item that costs $0.15. How much change do you get back?
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Answer: 85
- SubType
- make-change
- Difficulty
- hard
5 dimes + 2 pennies = ? cents
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Answer: 52
- SubType
- count-coins
- Difficulty
- hard
2 pennies + 5 pennies = ? cents
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Answer: 7
- SubType
- count-coins
- Difficulty
- hard
3 quarters + 2 nickels = ? cents
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Answer: 85
- SubType
- count-coins
- Difficulty
- hard
3 dimes + 2 nickels = ? cents
Show answer
Answer: 40
- SubType
- count-coins
- Difficulty
- hard
You pay $2.00 for an item that costs $1.90. How much change do you get back?
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Answer: 10
- SubType
- make-change
- Difficulty
- hard
$1.25 + $1.06 = ?
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Answer: 231
- SubType
- add-money
- Difficulty
- hard
You pay $1.00 for an item that costs $0.80. How much change do you get back?
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Answer: 20
- SubType
- make-change
- Difficulty
- hard
24 cents + $1.30 = ?
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Answer: 154
- SubType
- add-money
- Difficulty
- hard
$1.16 + $2.49 = ?
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Answer: 365
- SubType
- add-money
- Difficulty
- hard
Teaching Notes
Practice money counting dimes with free printable worksheets. Uniquely generated — reinforce key math skills with every set.
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